(5x+2)(2x^2-7x+3)=0

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Solution for (5x+2)(2x^2-7x+3)=0 equation:


Simplifying
(5x + 2)(2x2 + -7x + 3) = 0

Reorder the terms:
(2 + 5x)(2x2 + -7x + 3) = 0

Reorder the terms:
(2 + 5x)(3 + -7x + 2x2) = 0

Multiply (2 + 5x) * (3 + -7x + 2x2)
(2(3 + -7x + 2x2) + 5x * (3 + -7x + 2x2)) = 0
((3 * 2 + -7x * 2 + 2x2 * 2) + 5x * (3 + -7x + 2x2)) = 0
((6 + -14x + 4x2) + 5x * (3 + -7x + 2x2)) = 0
(6 + -14x + 4x2 + (3 * 5x + -7x * 5x + 2x2 * 5x)) = 0
(6 + -14x + 4x2 + (15x + -35x2 + 10x3)) = 0

Reorder the terms:
(6 + -14x + 15x + 4x2 + -35x2 + 10x3) = 0

Combine like terms: -14x + 15x = 1x
(6 + 1x + 4x2 + -35x2 + 10x3) = 0

Combine like terms: 4x2 + -35x2 = -31x2
(6 + 1x + -31x2 + 10x3) = 0

Solving
6 + 1x + -31x2 + 10x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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